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For a temperature difference `DeltaT=20.0^(@)C`, one slab of material conducts `10.0W//m^(2)` , another of the same shape conduct `20.0W//m^(2)`. What is the rate of heat flow `per m^(2)` of surface area whenthe slabs are placed side by side with `DeltaT_(tot)=20.0^(@)C` ? |
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Answer» `(dQ)/(dt)=(KADeltaT)/(l)=(DeltaT)/(RT_(1))` `10=(20)/(R_(1))impliesR_(1)=Q`unit Similarly `R_(2)=1` unit when placed side by side `implies` series combination `R_(new)=R_(1)+R_(2)` `implies (dQ)/(dt)=(DeltaT)/(R_(New))=(20)/(3unit)=(20)/(3)w//m^(2)` |
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