1.

For a string, tied with two fixed rigid supports, scparated by 75 cm has two consecutive harmonics at 315 Hz and 420 Hz. Find its minimum frequency.

Answer»

105 HZ
155 Hz
205 Hz
`10.5` Hz

Solution :Two consecutive HARMONICS, `f _(N) = n f _(1)`
`f _(n +1) =(n +1) f _(1)`
`therefore f_( n+1) - f _(n) = f _(1)`
`therefore f _(1) = 420 - 315 = 105 Hz`
`therefore f _(min) = f _(1) = 105 Hz`


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