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For a string, tied with two fixed rigid supports, scparated by 75 cm has two consecutive harmonics at 315 Hz and 420 Hz. Find its minimum frequency. |
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Answer» Solution :Two consecutive HARMONICS, `f _(N) = n f _(1)` `f _(n +1) =(n +1) f _(1)` `therefore f_( n+1) - f _(n) = f _(1)` `therefore f _(1) = 420 - 315 = 105 Hz` `therefore f _(min) = f _(1) = 105 Hz` |
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