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For a solution to form positive deviation,the solute-solvent interactions must be less than solute-solute and solvent-solvent interactions,making it easier for the molecules to escape in its pure form.still,why does the vapour pressure of the solution showing positive deviation increase compared to the pure form? |
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Answer» For a solution to form positive deviation,the solute-solvent interactions must be less than solute-solute and solvent-solvent interactions,making it easier for the molecules to escape in its pure form.still,why does the vapour pressure of the solution showing positive deviation increase compared to the pure form? |
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