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For a second order reaction, 2A product, a straight line is obtained if we plot : Concentration vs timeLog (conc) vs timeLog (conc) vs time-1Conc vs time |
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Answer» order to determine the rate law for a reaction from a set of data consisting of concentration (or the VALUES of some function of concentration) versus time, make three graphs.[A] versus t (linear for a zero order reaction)ln [A] versus t (linear for a 1st order reaction)1 / [A] versus t (linear for a 2nd order reaction)The graph that is linear indicates the order of the reaction with respect to A. Then, you can choose the correct rate equation:For a zero order reaction, rate = k (k = - slope of line)For a 1st order reaction, rate = k[A] (k = - slope of line)For a 2nd order reaction, rate = k[A]2 (k = slope of line)ExamplesFor a zero order reaction, as shown in the FOLLOWING figure, the plot of [A] versus time is a straight line with k = - slope of the line. Other graphs are curved for a zero order reaction.Graphs of concentration versus time, log concentration versus time and reciprocal of concentration versus time for a zero order reaction.For a first order reaction, as shown in the following figure, the plot of the logrithm of [A] versus time is a straight line with k = - slope of the line. Other graphs are curved for a first order reaction.Graphs of concentration versus time, log concentration versus time and reciprocal of concentration versus time for a first order reaction.For a SECOND order reaction, as shown in the following figure, the plot of 1/[A] versus time is a straight line with k = slope of the line. Other graphs are curved for a second order reaction.Graphs of concentration versus time, log concentration versus time and reciprocal of concentration versus time for a second order reaction.Top |
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