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For a reversible adiabatic ideal gas expansion `(dp)/(p)` is equal toA. `gamma(dV)/(V)`B. `-gamma(dV)/(V)`C. `((gamma)/(gamma-1))(dV)/(V)`D. `(dV)/(V)` |
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Answer» Correct Answer - B `PV^(gamma)` = constant, `P.gammaV^(gamma-1).dV+V^(gamma).dP=0` `therefore" "(dP)/(P)=-gamma.(dV)/(V)` |
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