For a reaction, N2O5⟶2NO2+12O2 Given: −d[N2O5]dt=k1[N2O5] d[NO2]dt – InterviewSolution

1.	For a reaction, N2O5⟶2NO2+12O2 Given: −d[N2O5]dt=k1[N2O5] d[NO2]dt=k2[N2O5] d[O2]dt=k3[N2O5] The relation between k1,k2 and k3 are:
Answer» For a reaction, $N_{2} O_{5} ⟶ 2 N O_{2} + \frac{1}{2} O_{2}$ Given: $\frac{- d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]$ $\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]$ $\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]$ The relation between $k_{1}, k_{2}$ and $k_{3}$ are:

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