For a reaction A+2B → C, the amount of C formed by starting the reac

1.	For a reaction A+2B → C, the amount of C formed by starting the reaction with 5 moles of A and 8 moles of B is(a) 5 moles(b) 8 moles(c) 16 moles(d) 4 moles
Answer» 1 mole of A reacts with 2 moles of B ⇒ 5 moles of A reacts with 10 moles of B but we have only 8 moles of B so B is the limiting reagent. Now 2 moles of B form 1 mole of C and 8 moles of B will form 4 moles of C-Hence answer is 4 moles.

For a reaction A+2B → C, the amount of C formed by starting the reaction with 5 moles of A and 8 moles of B is(a) 5 moles(b) 8 moles(c) 16 moles(d) 4 moles

Answer»

1 mole of A reacts with 2 moles of B ⇒ 5 moles of A reacts with 10 moles of B but we have only 8 moles of B so B is the limiting reagent.

Now 2 moles of B form 1 mole of C and 8 moles of B will form 4 moles of C-Hence answer is 4 moles.