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For a reaction, `2SO_(2(g))+O_(2(g))hArr2SO_(3(g))`, 1.5 moles of `SO_(2)` and 1 mole of `O_(2)` are taken in a 2 L vessel. At equilibrium the concentration of `SO_(3)` was found to be 0.35 mol `L^(-1)` The `K_(c)` for the reaction would beA. `5.1"L mol"^(-1)`B. `1.4"L mol"^(-1)`C. `0.6"L mol"^(-1)`D. `2.95"L mol"^(-1)` |
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Answer» Correct Answer - A `{:(,2SO_(2(g)),+,O_(2(g)),hArr,2SO_(3(g))),("Initial conc.",(1.5)/(2),,(1)/(2),,0),("At equilibrium ",(1.5)/(2)-0.35,,(1)/(2)-0.35,,0.35),(,=0.4,,=0.15,,=0.35):}` `K_(c)=((0.35)^(2))/(0.4xx0.4xx0.15)=5.1" L mol"^(-1)` |
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