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For a∈R (the set of all real numbers), a≠−1, limn→∞(1a+2a+⋯+na)(n+1)a−1[(na+1)+(na+2)+⋯+(na+n)]=160.Then a= |
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Answer» For a∈R (the set of all real numbers), a≠−1, limn→∞(1a+2a+⋯+na)(n+1)a−1[(na+1)+(na+2)+⋯+(na+n)]=160. |
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