1.

For a∈R (the set of all real numbers), a≠−1, limn→∞(1a+2a+⋯+na)(n+1)a−1[(na+1)+(na+2)+⋯+(na+n)]=160.Then a=

Answer»

For aR (the set of all real numbers), a1, limn(1a+2a++na)(n+1)a1[(na+1)+(na+2)++(na+n)]=160.

Then a=



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