For a projectile the ratio of maximum height reached to the square of

1.	For a projectile the ratio of maximum height reached to the square of flight time is(g=10m/s)
Answer» Answer: 5/4 Explanation: GIVEN : H=U²Sin²θ/2g T=2Usinθ/g now if we take the RATIO of MAXIMUM height reached to the square of flight TIME: H/T²=U²Sin²θ/2g/4U²sin²θ/g² =g/8 If we take g=10 m/s² then H/T²=10/8=5/4 hope it helps.......

For a projectile the ratio of maximum height reached to the square of flight time is(g=10m/s)

Answer»

Answer:

5/4

Explanation:

GIVEN :

H=U²Sin²θ/2g

T=2Usinθ/g

now if we take the RATIO of MAXIMUM height reached to the square of flight TIME:

H/T²=U²Sin²θ/2g/4U²sin²θ/g²

=g/8

If we take g=10 m/s² then

H/T²=10/8=5/4

hope it helps.......

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For a projectile the ratio of maximum height reached to the square of flight time is(g=10m/s)

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