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For a particle in `S.H.M.` if the amplitude of displacement is `a` and the amplitude of velocity is `v` the amplitude of acceleration isA. vaB. `(v^(2))/(a)`C. `(v^(2))/(2a)`D. `(v)/(a)` |
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Answer» Correct Answer - B Maximum velocity `v = omega a` Maximum acceleration `f = omega_(2) a` `rArr f = (v^(2))/(a)` |
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