1.

For a particle executing simple harmonic motion, the kinetic energy K is given by, K=K_(0)cos^(2)omegat The maximum value of potential energy is :

Answer»

`K_(0)`
`zero`
`K_(0)//2`
not obtainable

Solution :At theextreme the whole ENERGY is potential when `cos omegat.=1`
`:. U=K_(0)xx1=K_(0)`.
CORRECT CHOICE is (a).


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