Saved Bookmarks
| 1. |
For a mass of 2 kg, the velocity-time graph is given here. Find the force experiencedby the mass in regions OA, AB and BC. |
|
Answer» Force for OA = 4 N.Force for AB = 0 N.Force for BC = -4 N...Explanation:...For OA acceleration = 2 m/s² {change in VELOCITY / time}...so force = maF = 2×2= 4 N.F = 4 N...For AB there is no change in velocity so the work done = zero.For BC acceleration 0-20/10 { (velocity final- velocity initial)/time}acceleration = -20/10acceleration = -2 m/s²Force = ma = 2×-2= -4NForce = -4N... |
|