For a given YDSE experiment, List - 1 gives distance of a point from c

For a given YDSE experiment, List - 1 gives distance of a point from center C of the screen in mm and List - 2 gives resultant intensity at that point. I0 is intensity due to each slit at screen. Slit separation is d=0.2 mm. Distance of screen from slits is D=1 mm and wavelength of light is λ=400 nm. List -1 List - 2 (I) y=0 (P) 0 (II) y=0.5 (Q) I0 (III) y=1 (R) 2I0 (IV) y=43 (S) 3I0 (T) 4I0 (U) None If slit S1 and slit S2 are covered by thin films each of thickness 2000 nm and of refractive index 1.5 and 1.2 respectively, then match List - I with List - II

Answer»

For a given YDSE experiment, List - 1 gives distance of a point from center $C$ of the screen in $m m$ and List - 2 gives resultant intensity at that point.
$I_{0}$ is intensity due to each slit at screen. Slit separation is $d = 0.2 m m$ . Distance of screen from slits is $D = 1 m m$ and wavelength of light is $λ = 400 n m$ .

List -1	List - 2
(I) $y = 0$	(P) 0
(II) $y = 0.5$	(Q) $I_{0}$
(III) $y = 1$	(R) $2 I_{0}$
(IV) $y = \frac{4}{3}$	(S) $3 I_{0}$
	(T) $4 I_{0}$
	(U) None

If slit

S_{1}

and slit

S_{2}

are covered by thin films each of thickness

2000 n m

and of refractive index 1.5 and 1.2 respectively, then match List - I with List - II

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