For a given material, the rigidity modulus is ((1)/(3))^(rd) of Young's modulus. Its Poisson's ratio is

For a given material, the rigidity modulus is ((1)/(3))^(rd) of Young'

1.	For a given material, the rigidity modulus is ((1)/(3))^(rd) of Young's modulus. Its Poisson's ratio is
Answer» 0 0.25 0.3 0.5 Solution :The relationship of Poission.s ratio, RIGIDITY and Young.s modulus is `eta = Y/(2(1 - sigma))sigma` - Poisson.s ratio Here, `"" eta1/3 y implies 3 eta = y` Substituting the value, we GET `sigma = 0.5`