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For a given gas molecule at a fixed temperature, the area under the Maxwell-Boltzmann distribution curve is equal to(a) \(\frac{PV}{kT}\)(b) \(\frac{kT}{PV}\)(c) \(\frac{P}{NkT}\)(d) PV |
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Answer» Correct answer is (a) \(\frac{PV}{kT}\) |
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