For a circular loop of radius 0.02 m, the magnetic flux is 0.5×10−2 – InterviewSolution

1.	For a circular loop of radius 0.02 m, the magnetic flux is 0.5×10−2 weber. Calculate the strength of the magnetic field around the loop which is perpendicular to the plane of the loop.
Answer» For a circular loop of radius $0.02 m$ , the magnetic flux is $0.5 \times 10^{- 2} weber$ . Calculate the strength of the magnetic field around the loop which is perpendicular to the plane of the loop.

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