For a certain process, DeltaH=178 kJ and DeltaH=160 J/K . What is the – InterviewSolution

1.	For a certain process, DeltaH=178 kJ and DeltaH=160 J/K . What is the minimum temperature at which the process will be spontaneous ? Assume that DeltaH and DeltaS do not vary with temperature.
Answer» SOLUTION :When the PROCESS is at EQUILIBRIUM , `DeltaG=0` `:.DeltaH=TDeltaS` `(:.DeltaG=DeltaH-TDeltaS)` or `T=(DeltaH)/(DeltaS)=(178000)/(160)=1112.5K` THUS the process will become spontaneous above `1112.5K`

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