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For a certain gas `P_(c)` and `T_(c)` are `80atm` and `-33^(@)C` respectively then `V_(C)` of the gas will be approximately [Take `R=(1)/(2)" Ltr atm mol"^(-1)K^(-1)`]A. `(1)/(4)"Ltr mol"^(-1)`B. `(1)/(16)"Ltr mol"^(-1)`C. `(3)/(32)"Ltr mol"^(-1)`D. None of these |
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Answer» Correct Answer - 3 `(3)/(8)=(P_(0)V_(0))/(RT_(0))=(80xxV_(c))/((1)/(12)xx240)implies" "V_(c)=(3)/(32)` Litre`mol^(-1)` |
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