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For a cell, the terminal potential difference is `2.2 V`, when circuit is open and reduces to `1.8 V `. When cell is connected to a resistance `R=5Omega`, the internal resistance of cell `(R)` isA. `10/9Omega`B. `9/10 Omega`C. `11/9 Omega`D. `5/9 Omega` |
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Answer» Correct Answer - A `r=R(E/V-1)=5(2.2/1.8-1)=10/9Omega` |
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