For a body in S.H.M the velocity is given by the relation v= sqrt(144-16x^(2))m//"sec". The maximum acceleration is

For a body in S.H.M the velocity is given by the relation v= sqrt(144-

1.	For a body in S.H.M the velocity is given by the relation v= sqrt(144-16x^(2))m//"sec". The maximum acceleration is
Answer» `12 m//"SEC"^(2)` `16 m//"sec"^(2)` `36 m//"sec"^(2)` `48 m//"sec"^(2)` Answer :D