For a 3s-orbitalsΨ(3s)=19√3(1a0)3/2(6−6σ+σ2)e−σ/2;where σ=2 – InterviewSolution

1.	For a 3s-orbitalsΨ(3s)=19√3(1a0)3/2(6−6σ+σ2)e−σ/2;where σ=2r.Z3a0 What is the maximum radial distance of node from nucleus ?
Answer» For a 3s-orbitals $Ψ (3 s) = \frac{1}{9 \sqrt{3}} {(\frac{1}{a_{0}})}^{3 / 2} (6 - 6 σ + σ^{2}) e^{- σ / 2}; where σ = \frac{2 r . Z}{3 a_{0}}$ What is the maximum radial distance of node from nucleus ?

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