For a 3s− orbital: ψ(3s)=1a√3(1a0)32(6−6σ+σ2)e−σ2 Where σ – InterviewSolution

1.	For a 3s− orbital: ψ(3s)=1a√3(1a0)32(6−6σ+σ2)e−σ2 Where σ=2rZ3a0 What is the maximum radial distance of node from nucleus?
Answer» For a $3 s -$ orbital: $ψ (3 s) = \frac{1}{a \sqrt{3}} (\frac{1}{a_{0}})^{\frac{3}{2}} (6 - 6 σ + σ^{2}) e^{\frac{- σ}{2}}$ Where $σ = \frac{2 r Z}{3 a_{0}}$ What is the maximum radial distance of node from nucleus?

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