For 0.50 M aqueous solution of sodium cyanide, (pKb of CN− is 4.70) – InterviewSolution

1.	For 0.50 M aqueous solution of sodium cyanide, (pKb of CN− is 4.70), calculate(i) Hydrolysis constant(ii) Degree of hydrolysisiii) pHlog( 3.15 )=0.498Antilog (-9.3)=5.01×10−10
Answer» For 0.50 M aqueous solution of sodium cyanide, $({pK}_{b} {of CN}^{-} is 4.70)$ , calculate (i) Hydrolysis constant (ii) Degree of hydrolysis iii) pH log( 3.15 )=0.498 $Antilog (-9.3) = 5.01 \times 10^{- 10}$

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