1.

Following readings were obtained in the experiment to determine self inductance of a coil. If frequency of a.c. is 50 Hz, what is the value of self inductance ?

Answer» From D.C. Part.
`R_(1) = (V_(1))/(I_(1)) = (0.5)/(0.1) = 5 Omega, R_(2) = (0.6)/(0.12) = 5 Omega`
`:.` Average value of
`R = (R_(1) + R_(2))/(2) = (5 + 5)/(2) = 5 Omega`
`|{:(,"D.C.Part",),("S.No."," V"," I"),(1,0.5V,0.1A),(2,0.6V,0.12A):}| " " |{:(,"A.C.Part",),("S.No."," V"," I"),(1,1.0V,0.1A),(2,1.6V,0.16A):}|`
From A.C. Part
`Z_(1) = (V_(1))/(I_(1)) = (1.0)/(0.1) = 10 Omega , Z_(2) = (1.6)/(0.16) = 10 Omega`
Average value of
`Z = (Z_(1) + Z_(2))/(2) = (10 + 10)/(2) = 10 Omega`
As `X_(L) = omega L = 2 pi L = sqrt(Z^(2) - R^(2))`
`L = (sqrt(Z^(2) - R^(2)))/(2 pi v) = (sqrt(10^(2) - 5^(2)))/(2 xx 3.14 xx 50) = (sqrt 75)/(314)`
`= 0.0276 H`


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