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Following readings were obtained in the experiment to determine self inductance of a coil. If frequency of a.c. is 50 Hz, what is the value of self inductance ? |
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Answer» From D.C. Part. `R_(1) = (V_(1))/(I_(1)) = (0.5)/(0.1) = 5 Omega, R_(2) = (0.6)/(0.12) = 5 Omega` `:.` Average value of `R = (R_(1) + R_(2))/(2) = (5 + 5)/(2) = 5 Omega` `|{:(,"D.C.Part",),("S.No."," V"," I"),(1,0.5V,0.1A),(2,0.6V,0.12A):}| " " |{:(,"A.C.Part",),("S.No."," V"," I"),(1,1.0V,0.1A),(2,1.6V,0.16A):}|` From A.C. Part `Z_(1) = (V_(1))/(I_(1)) = (1.0)/(0.1) = 10 Omega , Z_(2) = (1.6)/(0.16) = 10 Omega` Average value of `Z = (Z_(1) + Z_(2))/(2) = (10 + 10)/(2) = 10 Omega` As `X_(L) = omega L = 2 pi L = sqrt(Z^(2) - R^(2))` `L = (sqrt(Z^(2) - R^(2)))/(2 pi v) = (sqrt(10^(2) - 5^(2)))/(2 xx 3.14 xx 50) = (sqrt 75)/(314)` `= 0.0276 H` |
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