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Following figure shows two processes A and B for a gas. If ∆QA and ∆QB are the amount of heat absorbed by the system in two cases, and ∆UA and ∆UB are changes in internal energies, respectively, then:(A) ∆QA = ∆QB; ∆UA = ∆UB(B) ∆QA > ∆QB; ∆UA = ∆UB(C) ∆QA < ∆QB; ∆UA < ∆UB(D) ∆QA > ∆QB; ∆UA > ∆UB |
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Answer» Answer: (B). will be correct ANSWERS HEAT is a path dependant process .and in process 1st volume change is more than process 2nd. Internal is state FUNCTION and in both process initial and final state is same .so change in internal energy will be zero. Explanation: hope the answer will help you Mark the answer brainliests please. |
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