Following figure shows on adiabatic cylindrical container of volume V0 divided by an adiabatic smooth piston (area of cross-section = A) in two equal parts. An ideal gas (CpCv=γ) is at pressure P1 and temperature T1 in left part and gas at pressure P2 and temperature T2 in right part. The piston is slowly displaced and released at a position where it can stay in equlibrium. The final common pressure of the two parts will be [Suppose x = displacement of the piston]

Following figure shows on adiabatic cylindrical container of volume V0

1.	Following figure shows on adiabatic cylindrical container of volume V0 divided by an adiabatic smooth piston (area of cross-section = A) in two equal parts. An ideal gas (CpCv=γ) is at pressure P1 and temperature T1 in left part and gas at pressure P2 and temperature T2 in right part. The piston is slowly displaced and released at a position where it can stay in equlibrium. The final common pressure of the two parts will be [Suppose x = displacement of the piston]
Answer» Following figure shows on adiabatic cylindrical container of volume $V_{0}$ divided by an adiabatic smooth piston (area of cross-section = A) in two equal parts. An ideal gas $(\frac{C_{p}}{C_{v}} = γ)$ is at pressure $P_{1}$ and temperature $T_{1}$ in left part and gas at pressure $P_{2}$ and temperature $T_{2}$ in right part. The piston is slowly displaced and released at a position where it can stay in equlibrium. The final common pressure of the two parts will be [Suppose $x$ = displacement of the piston]