1.

Following figure shows a network of eight resistors, each equal to 2 Omega , connected to a 3 V battery ofnegligible internal resistance. The current I in the circuit is :-

Answer»

0.25 A
0.50 A
0.75 A
1.0 A

Solution :Because of symmetry , BE and CF are ineffective
`therefore ` AB,BC and CD are in series . Total resistance
`R_1=6Omega`
AE,EF and FD are in series . Total resistance
`R_2=6Omega`
When they are is parallel , total resistance = `3Omega`
`therefore ` CURRENT =` (3V)/(3Omega)`=1.0 A


Discussion

No Comment Found

Related InterviewSolutions