five year age, father age was 7 times the age of his son 5 years later

1.	five year age, father age was 7 times the age of his son 5 years later the father age will be 3 times the age of his son find their present age
Answer» Step-by-step explanation: 5 years AGO, LET the AGE of the son be x years father's age = 7X years After 5 years, that is the present year son's age = x+5 years father's age = 7x+5 years 7x+5 = 3(x+5) 7x+5 = 3x+15 7x-3x = 15+5 4x = 20 x = 20/4 = 5 Son's age = 10 years Father's age = 40 years Hope this helps MARK AS BRAINLIEST

five year age, father age was 7 times the age of his son 5 years later the father age will be 3 times the age of his son find their present age

Answer»

Step-by-step explanation:

5 years AGO,

LET the AGE of the son be x years

father's age = 7X years

After 5 years, that is the present year

son's age = x+5 years

father's age = 7x+5 years

7x+5 = 3(x+5)

7x+5 = 3x+15

7x-3x = 15+5

4x = 20

x = 20/4

= 5

Son's age = 10 years

Father's age = 40 years

Hope this helps

MARK AS BRAINLIEST

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five year age, father age was 7 times the age of his son 5 years later the father age will be 3 times the age of his son find their present age​

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five year age, father age was 7 times the age of his son 5 years later the father age will be 3 times the age of his son find their present age