First and second ionization energies of magnesium are 7 and 15 eV resp – InterviewSolution

1.	First and second ionization energies of magnesium are 7 and 15 eV respectively. The amount of energy in kJ mol−1 needed to convert all the atoms of Magnesium into Mg2+ ions present in 12 mg of magnesium vapours is: (Report your answer upto two decimal)[Given: 1 eV=96.5 kJ mol−1]
Answer» First and second ionization energies of magnesium are $7$ and $15 eV$ respectively. The amount of energy in ${kJ mol}^{- 1}$ needed to convert all the atoms of Magnesium into $M g^{2 +}$ ions present in $12 mg$ of magnesium vapours is: (Report your answer upto two decimal) [Given: $1 eV = 96.5 {kJ mol}^{- 1}]$

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