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Findrealvalues of x and y if (1 +i)(xiy) 2-5i |
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Answer» Multiplying(1+i)(X+iy)=2-5i=x+iy+xi-y=2-5iComparing real and imaginary partsHencex-y=2y+X=-5Henceadd both equations2x=-3hencex=-3/2x-y=2-3/2-y=2y=-3/2-2y=-7/2 |
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