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Finde the standard deviation of first 21 natural number |
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Answer» Answer: The standard deviation of FIRST 21 natural number is √36.66 Step-by-step EXPLANATION: We know that б = √ [Σxi²/n - (Σxi/n)²] Σxi = [n * (n + 1)] / 2 .........(i) Σxi² = [n * (n + 1) * (2N + 1)] / 6 .........(ii) here, n = 21 now we have to put the VALUE of n in EQUATION (i) and (ii) Σxi = ( 21 * 22 ) / 2 = 231 Σxi² = ( 21 * 22 * 43 ) / 6 = 3311 now , б = √ [ (3311 / 21) - (231/21)² ] б = √ [ 157.66 - 11² ] б = √ [ 157.66 - 121 ] = √36.66 So the standard deviation of first 21 natural number is √36.66 |
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