1.

Find zeros and verify the relationship between 2 x square - 5x- 3

Answer» 2X^2 - 5X + 3

= 2x^2 - 2x - 3x + 3

= 2x ( X - 1) - 3(x - 1)

= (2x - 3) (x - 1)

Zeroes are 3/2 and 1

Now,

Sum of zeroes = - b/a

=> 3/2 + 1 = - (-5/2)

=> ( 3+ 2)/2 = 5 /2

=> 5 /2 = 5/2


LHS = RHS


Product of zeroes = c/a

=> 3/2 × 1 = 3/2

=> 3/2 = 3/2

LHS = RHS

Hence verified..


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