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Find zero of polynomial x2-8x+12 and verify relationship between zeros and coefficent of polynomial |
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Answer» Step-by-step explanation: The first TERM is, x^2 its coefficient is 1 . The middle term is, -8x its coefficient is -8 . The last term, "the CONSTANT", is +12 Step-1 : Multiply the coefficient of the first term by the constant 1 • 12 = 12 Step-2 : Find two factors of 12 WHOSE sum equals the coefficient of the middle term, which is -8 . -6 + -2 = -8 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and -2 x2 - 6x - 2x - 12 Step-4 : Add up the first 2 TERMS, pulling out like factors : x • (x-6) Add up the last 2 terms, pulling out common factors : 2 • (x-6) Step-5 : Add up the four terms of step 4 : (x-2) • (x-6) Which is the desired factorization x= 2 or x= 6. relationship between zeros and coefficent of polynomial.. α+β = -b/a. αβ =c/a. sum of zeroes =-b/a so,2+6 = -(-8)/1 8=8. product of zeroes =c/a . (2)(6) = 12/1. 12 = 12. |
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