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Find x³-y³,if x-y=5 and xy = 14 |
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Answer» x-y=5 xy=14 x3-y3= (x-y)(x2+xy+y2) =(5)(x2+14+y2) =(5)(x+y)2 =(5)(2×1×7) =(5)(15) =75 |
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