1.

Find x. If 62212x5 is a multiple of 3 and 11.

Answer»

Answer:

No NUMBER with given condition exists

Step-by-step explanation:

sum of digits in given number = 6+2+2+1+2+x+5 = 18+x

since 18 is ALREADY divisible by 3, so, for making the given number divisible by 3, x can TAKE any value which is multiple of 3 i.e. 0 or 3 or 6 or 9.

but , for making the number divisible by 11,

so difference of sum of alternate digits = (6+2+2+5)-(2+1+x)=15-(3+x)=12-x

so nearest multiple of 11 to 12 is 11 itself.

12-x=11

=>x=1

but when x=1 number will not be divisible by 3.

Hence, the given number with given conditions does not exists.

HOPE IT HELPS,

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