1.

Find x^2+√2x-4;if x=√3 and x=-2√2​

Answer»

ANSWER:

{x}^{2}  +  \sqrt{2} x - 4 \\ x =  \sqrt{3}  \\  {( \sqrt{3} )}^{2}  +  \sqrt{2}  \sqrt{3}  - 4 \\  = 3 +  \sqrt{6}  - 4 \\  =  \sqrt{6 }  - 1



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