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Find value under root162 upon under root 2 |
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Answer» Answer: Hey FRIEND, Here is the answer you were looking for: \frac{ \sqrt{162} }{ \sqrt{2} } \\ Splitting we get, = \frac{ \sqrt{2 \TIMES 9 \times 9} }{ \sqrt{2} } \\ \\ = \frac{9 \sqrt{2} }{ \sqrt{2} } \\ On RATIONALIZING the DENOMINATOR we get, = \frac{9 \sqrt{2} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ = \frac{9 \sqrt{2} \times \sqrt{2} }{ {( \sqrt{2} )}^{2} } \\ \\ = \frac{9 \times 2}{2} \\ \\ = 9 Step-by-step EXPLANATION: |
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