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Find value of ` Sin ( tan^(-1) x)` |
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Answer» Let `tan^-1x = theta` Then, `x = tan theta` `=>tan theta = x/1` `:. sin theta = x/sqrt(x^2+1^2)` `=>sin theta = x/sqrt(x^2+1)->(1)` Now, `sin(tan^-1x ) = sin theta` From (1), `sin(tan^-1x ) = x/sqrt(x^2+1)` |
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