1.

Find value of p(x)=x^3-3x^2+1at x=-2,x=1and x=0​

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ANSWER:

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Step-by-step explanation:

when x=-2

p(-2)=(-2)^3-3(-2)^2+1

=(-8)-12+1

=-19

when x=1

p(1)=(1)^3-3(1)^2+1

=1-3+1

=-1

when x=0

p(0)=(0)^3-3(0)^2+1

=1


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