1.

Find value of kequation has equal2x²+ kx+2=0​

Answer»

Answer:

heyy hope this helps u

Step-by-step explanation:

The VALUES of k = 4.

Given:

Quadratic EQUATION 2X^{2}+Kx +2=02x

2

+Kx+2=0 has equal roots.7

To find:

The values of k

Explanation:

General format of quadratic equation is ax^2+bx+c =0ax

2

+bx+c=0 .

If the roots of quadratic equation is equal then,

\sqrt{B^{2} \ -\ 4ac }=0

b

2

− 4ac

=0

Where,

a = coefficient of x²

b = coefficient of x

c = constant term.

\sqrt{b^{2} \ -\ 4ac }=0

b

2

− 4ac

=0

b² - 4ac =0

Comparing the quadratic equation

2x^{2}+Kx +2=02x

2

+Kx+2=0

b = k a=2 c=2

k² - 4×2×2 = 0

k² = 16

k = \sqrt{16}

16

k = 4

Therefore, the values of k = 4 if roots are equal.

To learn more...

1. If alpha and beta are roots of quadratic equation 3x2+kx+8 and alpha/beta=2/3 then find the VALUE of k

2. The sum of the roots of a quadratic equation is 3 while the sum of the squares of its roots is 7. find the equation.


Discussion

No Comment Found

Related InterviewSolutions