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Find two possible pairs of numberssuch that the HCF and L.C.M ofeach pair of numbers are 21 and630, respectively. |
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Answer» LCM and HCF of two numbers are given we have to find the numbers. Let HCF of two numbers be 21 and LCM be 630. Let numbers be x and y. x = 21a and y=21b, where a and b are relative prime to each others. 21ab = LCM of x and y ab = 630/21 = 30 Now find a and b relative prime to each others and ab=30. Thus (1,30), (2,15), (3, 10), (5, 6). The possible numbers are (21, 630), (42, 315), (63, 210), (105, 126). |
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