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Find three numbers in A.P. whose sum is 21 and product is 315 |
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Answer» Nice answer Nice a-d,a,a+da-d+a+a+d=213a=21a=7product=a-d*a*a+=315multiply them u will get value of d=2subsitute the value in a-d,a,a+dnumbers are 5,7,9 Let the number be (a-d), a, (a+d)(a-d)+a+(a+d)=21a-d+a+a+d=213a=21a=7(a-d)×a×(a+d)=231(a²-d²)×7=231a²-d²=337²-d²=3349-d²=33d²=49-33d²=16d=4Numbers = 3,7,11 |
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