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Find three consecutive whole numbers whose sum is more than 45 but less than 54. |
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Answer» Let the three consecutive whole numbers be (x – 1), x and (x + 1). ∴ Sum of the three numbers = (x – 1) + x + (x + 1) = 3x Given that, the sum of the three numbers is greater than 45 and less than 54. When the sum of the three numbers is 45, 3x = 45 ∴ x = 45/3 ∴ x = 15 When the sum of the three numbers is 54, ∴ 3x = 54 ∴ x = 54/3 ∴ x = 18 ∴ the value of x is greater than 15 and less than 18. ∴ the value of x is either 16 or 17. Case I: If the value of x is 16, then the three consecutive whole numbers are (16 – 1), 16,(16 + 1)i.e., 15, 16, 17 Case II: If the value of x is 17, then the three consecutive whole numbers are (17 – 1), 17, (17 + 1) i.e., 16, 17, 18. ∴ The three consecutive whole numbers are 15, 16, 17 or 16, 17, 18. |
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