Find three consecutive natural numbers such that the sum of the first

1.	Find three consecutive natural numbers such that the sum of the first and second is 15 more than the third.
Answer» Let first number be x. According to the question second number is x + 1 and the third is x + 2 Sum of first and second numbers = (x) + (x + 1). According to question: ⇒ (x) + (x + 1) = 15 + (x + 2) ⇒ 2x + 1 = 17 + x Transposing x to LHS and 1 to RHS, we get ⇒2x – x = 17 – 1 ⇒ x = 16 So, first number = x = 16, Second number = x + 1 = 16 + 1 = 17 And third number = x + 2 = 16 + 2 = 18 Thus, the required consecutive natural numbers are 16, 17 and 18.

Find three consecutive natural numbers such that the sum of the first and second is 15 more than the third.

Answer»

Let first number be x.

According to the question second number is x + 1 and the third is x + 2

Sum of first and second numbers = (x) + (x + 1).

According to question:

⇒ (x) + (x + 1) = 15 + (x + 2)

⇒ 2x + 1 = 17 + x

Transposing x to LHS and 1 to RHS, we get

⇒2x – x = 17 – 1

⇒ x = 16

So, first number = x = 16,

Second number = x + 1 = 16 + 1 = 17

And third number = x + 2 = 16 + 2 = 18

Thus, the required consecutive natural numbers are 16, 17 and 18.