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Find three consecutive integers such that their sum is 78. |
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Answer» Sum of three consecutive numbers = 78 Let first number = x Then second number = x + 1 and third number = x + 2 Then x + x+1+x + 2 = 78 ⇒ 3x + 3 = 78 ⇒ 3x = 78 – 3 = 75 ⇒ x = 75/ 3 = 25 ∴ First number = 25 Second number = 25 + 1 = 26 and third number = 26 + 1 = 27 Then the three required numbers are 25, 26,27 |
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