1.

find three consecutive even numbers such that the sum of the first and the last number exceeds the second number by 10

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These EVEN numbers are in A.P,

They are (a - d), (a), (a + d)

(a - d) + (a+d) = a+ 10

a - d + a + d = a + 10

'd' get CANCELLED,

2a = a + 10

a = 10

For CONSECUTIVE even numbers, 'd' = 2

So, the numbers are:

a-d = 10-2 = 8

a = 10

a + d = 10+2 = 12


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