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Find the zeros of the quadratic polynomial and Verifythe relationship betweenthe cofficients X²- 10X + 25 =0 |
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Answer» Answer: first you have to split it X2 -10X + 25 =0 x2 -(5x-5x) + 25 =0 x2-5x -5x + 25 x(x-5) -5 (x-5) (x-5) (x-5) let p(x) = x2-10x+25 the zeros is (x-5)(x-5) when it happens x=5 , x=5 The relationship of POLYNOMIAL is sum of ZERO = -b/a product of zero = c/a Here a=1 , b=-10 ,c=25 sum of the zero = 5+5 = -(-10)/1 10 =10 (verify) Now you have to find product of zero 5×5 =25/1 25 =25 (verify) I hope you will understand. about it Thank you |
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