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Find the zeros of the polynomials given below:(i) p(x) = x-5(ii) q(x) = x + 4(iv) p(x) = ax + b (v) r(x) = x2 + 3x(iii) h(x) = 6x - 1(vi) (x) = x2 + 2x +1 |
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Answer» Answer: 1) x-5=0 x=5 hence the zero is 5 2) x+4=0 x=-4 hence the zero is -4 3) ax+b=0 ax=-b x=-b/a hence the zero is -b/a 4) 6x-1=0 6x=1 x=1/6 hence the zero is 1/6 5) x^2+2x+1 = x^2+x+x+1 = (x^2+x) (x+1) = x(x+1) +1(x+1) = ( x+1 ) ( x+1 ) = x+1=0 = x=-1 hence the zero of the polynomial are -1 and -1 plz MARK my answer as the brainliest hope it helps U |
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