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Find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients:• x²+ 7x + 12• x² - 2x -8Hi Sourabhk178It's second chance...Last left.​

Answer»

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Step-by-step EXPLANATION:

The given QUADRATIC polynomial is,

p(x) =4x² - 4x - 3

=> 4x² - 6x + 2x - 3

=> 2x( 2x -3) + 1(2x + 3)

=> (2x + 1) (2x -3)

p(x) = 0

(2x + 1) = 0 or (2x-3) = 0

x=-1/2 or x= 3/2

Hence, -1/2 and 3/2 are the zeroes of p(x).

Sum of zeroes = -1/2 + 3/2 = 2/2 = 1 = Coefficient of x / Coefficient of x²

Product of zeroes = (-1/2)(3/2) = -3/4 = CONSTANT term/ Coefficient of x²

Hope this would help you!!



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